[lug] c question, int passed by reference

[Carl Wagner]

I needed to create a small program that used an integer that was passed 
by reference.
It passed fine but I could not increment the value of the integer, but I 
could increment the pointer.
I finally resorted to doing an l = l+1; .


So why aren't the following functions, 'a' and 'b', the same?  'b' works 
as expected,  but 'a' increments the pointer
This is what I would expect if I did "k++" (without the asterisk).

Thanks,
Carl.
=================================

#include <stdio.h>

void a(int *k);
void b(int *l);

int
main(void)
{
   int i,j,x;
 
   i = 3;
   a(&i);

   j = 7;
   b(&j);
}

void a(int *k)
{
   printf("a1>  k = %u\n", k);
   printf("a1> *k = %u\n", *k);
   *k++; 
   printf("a2>  k = %u\n", k);
   printf("a2> *k = %u\n\n", *k);

}

void b(int *l)
{
   printf("b1>  l = %u\n", l);
   printf("b1> *l = %u\n", *l);
   *l = *l +1;
   printf("b2>  l = %u\n", l);
   printf("b2> *l = %u\n", *l);

}




================
Output


a1>  k = 3220283020
a1> *k = 3
a2>  k = 3220283024
a2> *k = 6550480

b1>  l = 3220283016
b1> *l = 7
b2>  l = 3220283016
b2> *l = 8