[lug] delete last character of every line

[Zan Lynx]

On Wed, 2005-03-23 at 14:33 -0700, Shannon Johnston wrote:
> Once again, I'm stuck with a little problem.
> I've got a list of 6000 ip addresses in a text file, all of them have a
> trailing ".". I need to get rid of that before it becomes useful.
> 
> Does anybody know how to do that? Either in vi or as a sed command?

In vi or sed it is roughly the same.
vi:
:%s/.$//

or
sed -e 's/.$//'

Pretty sure...didn't test either one though.
In regex, the . means any character and $ means end of line, so both
expressions mean substitute "any character" just before "end of line"
with nothing (the nothing in between //)
-- 
Zan Lynx <zlynx at acm.org>
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