[lug] Stripping whitespace in a shell script

[rm at fabula.de]

On Wed, Feb 20, 2002 at 10:04:46AM -0700, Riggs, Rob wrote:
> Thanks Chip. But that sed script will only strip spaces. I'm looking to
> strip all whitespace, not just " ", but also newlines, tabs, etc.

How about:

  sed -e 's/[\n\t\r ]*$//'

You can insert all sorts of characters into the '[  ... ]' construct,
depending on your dfinition of whitespace.

   Ralf

> -----Original Message-----
> From: Chip Atkinson [mailto:chip at rmpg.org]
> Sent: Wednesday, February 20, 2002 9:55 AM
> To: 'lug at lug.boulder.co.us'
> Subject: Re: [lug] Stripping whitespace in a shell script
> 
> 
> You could use sed.  For example,
> sed -e "s/  *$//"
> This works in the test that I just ran.
> 
> Chip
> 
> On Wed, 20 Feb 2002, Riggs, Rob wrote:
> 
> > I'm looking for an effecient way to strip whitespace from the trailing end
> > of a line of text in a shell script.
> >
> > I was using "awk '{print $1}'", but it breaks down when there is embedded
> > whitespace in the text, spitting out only the portion prior to the first
> > embedded whitespace. While whitespace should not be embedded, it occurs
> > frequently enough that I need to deal with it.
> >
> > Any suggestions on how to do it in Bash script?
> >
> > -Rob
> >
> >
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