[lug] Stripping whitespace in a shell script

[Scott A. Herod]

Won't [:space:] also do it?

rm at fabula.de wrote:
> 
> On Wed, Feb 20, 2002 at 10:04:46AM -0700, Riggs, Rob wrote:
> > Thanks Chip. But that sed script will only strip spaces. I'm looking to
> > strip all whitespace, not just " ", but also newlines, tabs, etc.
> 
> How about:
> 
>   sed -e 's/[\n\t\r ]*$//'
> 
> You can insert all sorts of characters into the '[  ... ]' construct,
> depending on your dfinition of whitespace.
> 
>    Ralf
> 
> > -----Original Message-----
> > From: Chip Atkinson [mailto:chip at rmpg.org]
> > Sent: Wednesday, February 20, 2002 9:55 AM
> > To: 'lug at lug.boulder.co.us'
> > Subject: Re: [lug] Stripping whitespace in a shell script
> >
> >
> > You could use sed.  For example,
> > sed -e "s/  *$//"
> > This works in the test that I just ran.
> >
> > Chip
> >
> > On Wed, 20 Feb 2002, Riggs, Rob wrote:
> >
> > > I'm looking for an effecient way to strip whitespace from the trailing end
> > > of a line of text in a shell script.
> > >
> > > I was using "awk '{print $1}'", but it breaks down when there is embedded
> > > whitespace in the text, spitting out only the portion prior to the first
> > > embedded whitespace. While whitespace should not be embedded, it occurs
> > > frequently enough that I need to deal with it.
> > >
> > > Any suggestions on how to do it in Bash script?
> > >
> > > -Rob